Jak vypočítat a) sin 5/6 π b) cos 3/4π c) sin210° d)cos(-180°) ?

Odpovědi

sin(5*pi/6)=sin(pi-(pi/6)=sin(pi/6)=1/2
cos(3*pi/4)=cos(pi-(pi/4)=-cos(pi/4)=-√2/2
sin(210°)=sin(180°+ 30°)=-sin(30°)=-1/2
cos(-180°)=cos(180°)=-1

sin(3*pi/4)

sin(3*pi/4) = 1/√2 = √2/2