Je dán kartézský součin E x F = {[3; 2]; [k; m]; [k; 2]; [1; m] [1; 2]; [3; m]}. Urči množiny E, F.
Odpovědi
Diskuze
F={2,m}
E x F = {[3; 2]; [k; m]; [k; 2]; [1; m] [1; 2]; [3; m]}
F={2,m}
E x F = {[3; 2]; [k; m]; [k; 2]; [1; m] [1; 2]; [3; m]}
F={2,m}
E x F = {[3; 2]; [k; m]; [k; 2]; [1; m] [1; 2]; [3; m]}