faktorial
(n+2)! / n! + (n+1)! x (n+1) = (n-4)! / (n-5)! + 3
Odpovědi
Diskuze
(n+2)(n+1)n! / [n! +(n+1)n!] * (n+1) = (n-4)(n-5)!/(n-5)! + 3
(n+2)(n+1)n!/[n!(1+n+1)] * (n+1) = (n-4) + 3
(n+2)(n+1)/(n+2) * (n+1) = n-1
(n+1)(n+1) = n-1
n^2 + 2n + 1 = n-1
n^2 + n + 2 =0
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