kolik alkoholu vznikne z 1500 glukozy
Odpovědi
Diskuze
m(C6H12O6) = 1500 g
M(C6H12O6) = 180 g/mol
n(C6H12O6) = m/M = 1500/180 = 8,33 mol
n(CH3CH2OH) = 2*n(C6H12O6) = 2*8,33 = 16,67 mol
n = m/M => m = M(CH3CH2OH)*n = 46*16,67 = 766,82 g
m(C6H12O6) = 1500 g
M(C6H12O6) = 180 g/mol
n(C6H12O6) = m/M = 1500/180 = 8,33 mol
n(CH3CH2OH) = 2*n(C6H12O6) = 2*8,33 = 16,67 mol
n = m/M => m = M(CH3CH2OH)*n = 46*16,67 = 766,82 g