jak zderivuju 1 / 3x^3
jak zderivuju 1 / 3x^3 děkuji
Odpovědi
Diskuze
(x^n)' = n*x^(n-1)
(1/3x^3))' = (1/3 * x^-3)' = 1/3*-3x^-4 = -x^-4 = -1/(x^4)
http://www.wolframalpha.com/input/?i=%281%2F3+*+x%5E-3%29%27
(x^n)' = n*x^(n-1)
(1/3x^3))' = (1/3 * x^-3)' = 1/3*-3x^-4 = -x^-4 = -1/(x^4)
http://www.wolframalpha.com/input/?i=%281%2F3+*+x%5E-3%29%27